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7x^2+13x=15
We move all terms to the left:
7x^2+13x-(15)=0
a = 7; b = 13; c = -15;
Δ = b2-4ac
Δ = 132-4·7·(-15)
Δ = 589
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-\sqrt{589}}{2*7}=\frac{-13-\sqrt{589}}{14} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+\sqrt{589}}{2*7}=\frac{-13+\sqrt{589}}{14} $
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